Integrand size = 21, antiderivative size = 9 \[ \int \frac {x}{\sqrt {1+a^2 x^2} \text {arcsinh}(a x)} \, dx=\frac {\text {Shi}(\text {arcsinh}(a x))}{a^2} \]
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Time = 0.05 (sec) , antiderivative size = 9, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {5819, 3379} \[ \int \frac {x}{\sqrt {1+a^2 x^2} \text {arcsinh}(a x)} \, dx=\frac {\text {Shi}(\text {arcsinh}(a x))}{a^2} \]
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Rule 3379
Rule 5819
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {\sinh (x)}{x} \, dx,x,\text {arcsinh}(a x)\right )}{a^2} \\ & = \frac {\text {Shi}(\text {arcsinh}(a x))}{a^2} \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 9, normalized size of antiderivative = 1.00 \[ \int \frac {x}{\sqrt {1+a^2 x^2} \text {arcsinh}(a x)} \, dx=\frac {\text {Shi}(\text {arcsinh}(a x))}{a^2} \]
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Time = 0.24 (sec) , antiderivative size = 10, normalized size of antiderivative = 1.11
method | result | size |
default | \(\frac {\operatorname {Shi}\left (\operatorname {arcsinh}\left (a x \right )\right )}{a^{2}}\) | \(10\) |
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\[ \int \frac {x}{\sqrt {1+a^2 x^2} \text {arcsinh}(a x)} \, dx=\int { \frac {x}{\sqrt {a^{2} x^{2} + 1} \operatorname {arsinh}\left (a x\right )} \,d x } \]
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\[ \int \frac {x}{\sqrt {1+a^2 x^2} \text {arcsinh}(a x)} \, dx=\int \frac {x}{\sqrt {a^{2} x^{2} + 1} \operatorname {asinh}{\left (a x \right )}}\, dx \]
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\[ \int \frac {x}{\sqrt {1+a^2 x^2} \text {arcsinh}(a x)} \, dx=\int { \frac {x}{\sqrt {a^{2} x^{2} + 1} \operatorname {arsinh}\left (a x\right )} \,d x } \]
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\[ \int \frac {x}{\sqrt {1+a^2 x^2} \text {arcsinh}(a x)} \, dx=\int { \frac {x}{\sqrt {a^{2} x^{2} + 1} \operatorname {arsinh}\left (a x\right )} \,d x } \]
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Timed out. \[ \int \frac {x}{\sqrt {1+a^2 x^2} \text {arcsinh}(a x)} \, dx=\int \frac {x}{\mathrm {asinh}\left (a\,x\right )\,\sqrt {a^2\,x^2+1}} \,d x \]
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